O=C(CCl)N1CCN(S(=O)(=O)c2ccc(Cl)cc2)C[C@@H]1Oc1ccc(F)cc1
O=C(CCl)N1CCN(S(=O)(=O)c2ccc(Cl)s2)C[C@@H]1Oc1ccc(F)cc1
O=C(CCl)N1CCN(S(=O)(=O)c2ccc(Cl)s2)[C@@H](CCc2ccccc2O)C1
O=C(CCl)N1CCN(S(=O)(=O)c2ccc(Cl)cc2)[C@@H](CCc2ccccc2O)C1
Combining fragments. Sorry about the chiral centre! May be worth trying both enantiomers / racemic especially in the case of the phenol variants due to the flexible chain.